BEST Air Intake For the 6.2L?

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pat247

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How would you differentiate between gains solely from the cai ?

You wouldn't, what you would know is what the combination of tune and CAI gave you and that is all I care about. I know there are gains with a 91 performance tune from Livernois and the stock airbox. If they can write a 91 performance tune for the modified CAI and I get no MIL I'll be a happy camper cause I like the sound of the truck with the CAI.
 

Livernois Motorsports

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We use our Windstorm CAI on the Raptors. We have them in stock and ready to go!
PM me for pricing, or give us a call!

Brandon
 

AngryBird

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Write this down:

ANY OUTFIT THAT CLAIMS HP GAINS or MILEAGE GAINS FROM THEIR CAI IS LYING.

There is no magic, just the laws physics and chemistry. You want an intake that will do nothing more or less than come closest to the stoichiometric optimum at all throttle openings and flow rates. That's all there is. All of the rest is marketing ********. Ask for the dyno sheets on your specific engine that show the air/fuel curve, not just the HP and Torque curves. If they can't or won't eagerly provide that, walk away.

What you said is true if the computer does not adjust for the increased amount of air.

Stoichiometry describes the chemical reaction in a quantitative way and lets you know the amount of excess and limiting reagents. However if you increase the amount of the reagents proportionally (keeping the Stoichiometric equation in balance), the exothermic reaction releases more energy. So if your computer can increase the fuel proportionally when it sees an increase in air, you have gains from the CAI. That is how a supercharger works, It packs more oxygen into the cylinder to react with more gasoline. Of course most of the time the stock injectors can't keep up so you have to change them in order to keep the correct balance of oxygen to octane.

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

This reaction releases 10 arbitrary units of energy.

20 C8H18 + 250 O2 → 160 CO2 + 180 H2O

This reaction will put out 100 units of arbitrary energy.
 

Ruger

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"...if you increase the amount of the reagents proportionally (keeping the Stoichiometric equation in balance), the exothermic reaction releases more energy."

Correct. But absent other changes to the engine in question, it will only draw as much fuel/air mixture as it can draw at any rpm. If you make no changes to the engine (turbo, blower, compression ratio, etc.), then you don't "increase the amount of reagents." You could put an air filter as big as a house on the 6.2L and it'll still produce the power of a 6.2L unless you make changes to it. And if you do make those changes, then the resultant power increase will be attributable to the changes you've made and not to the nature of the air filter.

An unregarded but important factor that is often overlooked is airspeed or flow rate. This is usually considered with regard to exhaust system design. In an unbridled effort to reduce restrictions in the exhaust tract, you can design a system that has such big tubes that the exhaust flow will actually stall at lower rpms. The resultant system will operate as designed at wide open throttle, but will perform like shit at lesser flow rates. The same mistake can be made in intake systems with the same very bad results.

You can have too much of a good thing. As in virtually everything, there is a sweet spot.
 

AngryBird

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^^^ Awesome
______________________________

As far as the intake is concerned, lets look at the givens of the problem:

1. Restrictions cause a pressure drop. (see the Poiseuille Equation if you believe this not to be true)

2. If you assume that the CAI offers less restriction than the stock filter(which you can convince your self of by trying to breath through different size straws), that means the Volumetric Flow rate increases.

3. The Volumetric Flow rate is directly proportional to the Mass Flow Rate.
Mass Flow rate is defined as: the mass of a substance (in our case the oxygen in air) which passes through a given surface per unit of time.

Mass flow rate relates to volumetric flow rate by the following equation:

ṁ = ρ V (Mass = Density x Volume)

4. The Law of the conservation of mass tells us that the mass of air going through the intake filter must = the mass that is going into the engine intake, and therefore the intake valves and into the cylinder. That means that you get an increased mass of Air flowing into the cylinder when the intake valve is open.

5. More mass (number of molecules) in a constant volume (the cylinder at any given point in its stroke) causes a higher pressure within that volume. See the Ideal Gas Law to prove this.

Note: At this point, if nothing else has changed, the CAI causes no gain in power because there isn't enough gasoline to react with the increased air mass (as discussed above with Stoichiometry).

However something does change!

6. The engine control module reads data from the Mass Airflow Sensor and the O2 sensor and adjusts for the lean condition (caused by too much air) by increasing the fuel. Now the engine has balanced the fuel/air ratio which means you now have more fuel and more air in the cylinder.

7. With more air and more fuel, the potential chemical energy has increased. When the spark plug fires and the fuel ignites you get a greater pressure spike in the cylinder than you would have with less pressure and less fuel.

8. This high pressure caused by combustion creates more force on the cylinder over the distance of the down stroke. Force over a distance is known as Work. An increase in Work over a constant amount of time (i.e. the time it takes for the cylinder to go from TDC to the bottom of its stroke) is Power. Increased Pressure means increased Work over the same amount of time means increased Power.

Here are the equations:

Force = Pressure x Area
Work = Force x Distance
Power = Work / Time

I believe Everything above to be true throughout any single cycle of the engine regardless of engine speed.

To say that a CAI cannot increase power is just plain wrong. I believe I have proved it here with the application of Physics.

and yes I'm very bored today...
 
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